The free expansion of an ideal gas is an adiabatic process and so no heat is transferred.

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The free expansion of an ideal gas is an adiabatic process and so no heat is transferred. No work is done, so the internal energy does not change. Thus, Q/T = 0, yet the randomness of the system and thus its entropy have increased after the expansion. Why does Eq. (20.19) not apply to this situation?


Eq.(20.19)

- Upper limit = final state Entropy change in a reversible process- Infinitesimal heat AS = flow into system T* Absolute

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University Physics with Modern Physics

ISBN: 978-0133977981

14th edition

Authors: Hugh D. Young, Roger A. Freedman

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