Suppose HX( z) is the probability- generating function of some random variable X with PMF PX( k)
Question:
(a) HY (z) = HX (z / 2)
(b) HY (z) = HX 2 = ( z) .
(c) HY (z) = zmHX( z) .
(d) HY (z) = HX( z– 1).
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a HY z may not be the PGF o...View the full answer
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Related Book For 
Probability and Random Processes With Applications to Signal Processing and Communications
ISBN: 978-0123869814
2nd edition
Authors: Scott Miller, Donald Childers
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