Question: Suppose that xy + y3 = 2. Then implicit differentiation twice with respect to x yields in turn: (a) xy' + y + 3y2y' =

Suppose that xy + y3 = 2. Then implicit differentiation twice with respect to x yields in turn:
(a) xy' + y + 3y2y' = 0'
(b) xy" + y' + y' + 3y2y" + 6y(y')2 = 0.

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