The actual solutions to the initial-value problems in Exercise 1 are given here. Compare the actual error at each step to the error bound.
a. y(t) = 1/5 te3t - 1/25e3t + 1/25e−2t
b. y(t) = t + 1/(1 - t)
c. y(t) = t ln t + 2t
d. y(t) = 1/2sin 2t - 1/3 cos 3t + 4/3