The actual solutions to the initial-value problems in Exercise 2 are given here. Compute the actual error and compare this to the error bound if Theorem 5.9 can be applied.
a. y(t) = ln(et + e − 1)
b. y(t) = √(t2 + 2t + 6) − 1
c. y(t) =(t − 2 +√2ee−t/2)2
d. y(t) = (4 + cos 2 − cos 2t)/2t2