Question: The bowling ball shown rolls without slipping on the horizontal xz plane with an angular velocity = xi + yj + zk. Knowing that
The bowling ball shown rolls without slipping on the horizontal xz plane with an angular velocity ω = ωxi + ωyj + ωzk. Knowing that vA = (14.4 ft/s)i (14.4 ft/s)j + (10.8 ft/s)k and D (28.8 ft/s) v = i+ (21.6 ft/s)k, determine (a) The angular velocity of the bowling ball, (b) The velocity of its center C.

B CL D 4.3 in.
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Radius of ball 43 in 035833 ft At the given instant ... View full answer
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