The circuit here is made of two batteries (6 volt and 9 volt) and three resistors (47 ohms, 470 ohms, and 280 ohms). The batteries create an electric current in the circuit. Let x, y, and z represent the current in amps flowing through each resistor. The voltage across each resistor is current times resistance (V = IR). This gives two equations for the two loops of the circuit:
47x + 470y = 6...................280z + 470y = 9
The electric current flowing into any point along the circuit must flow out. So, for instance, at junction A, x + z - y = 0. Find the current flowing through each resistor.

Transcribed Image Text:

6 V 9 V 다나.