Question: The differential cross section that will cause particles to scatter at an angle 55° off a target is 4.0-10-18 m2/sr. A detector with an area

The differential cross section that will cause particles to scatter at an angle 55° off a target is 4.0-10-18 m2/sr. A detector with an area of 1.0 cm2 is placed 1.0 m away from the target in order to detect particles that have been scattered at 55°. If 3.0-1017 particles hit the 1.0-mm2-area target every second, how many will strike the detector every second?

Detector area = 1.0 cm. Target 1 1.0 m

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