Question: The effective cross section of a gold nucleus corresponding to the scattering of mono energetic alpha particles within the angular interval from 90 to 180

The effective cross section of a gold nucleus corresponding to the scattering of mono energetic alpha particles within the angular interval from 90° to 180° is equal to ∆o = 0.50 kb. Find:
(a) The energy of alpha particles;
(b) The differential cross section of scattering dσ/dΩ (kb/sr) corresponding to the angle 0 = 60%

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