Question: The efficiency ratio for a steel specimen immersed in a phosphating tank is the weight of the phosphate coating divided by the metal loss (both

The efficiency ratio for a steel specimen immersed in a phosphating tank is the weight of the phosphate coating divided by the metal loss (both in mg/ft2). The article "Statistical Process Control of a Phosphate Coating Line" (Wire J. Intl., May 1997: 78-81) gave the accompanying data on tank temperature (x) and efficiency ratio (y).

The efficiency ratio for a steel specimen immersed in a

a. Construct stem-and-leaf displays of both temperature and efficiency ratio, and comment on interesting features.
b. Is the value of efficiency ratio completely and uniquely determined by tank temperature? Explain your reasoning.
c. Construct a scatter-plot of the data. Does it appear that efficiency ratio could be very well predicted by the value of temperature? Explain your reasoning.

Temp. | 170 172 173 174 174 175 176 Ratio 84 1.31 1.42 1.03 1.07 1.08 1.04 Temp. 177 180 180 180 180 180 181 Ratio 1.80 1.45 1.60 2.13 2.15 84 Temp.181 182 182 182 182 184 184 Ratio 1.43 90 1.81 .94 2.68 1.49 2.52 Temp.|185 186188 Ratio 3.00 1.87 3.08

Step by Step Solution

3.48 Rating (165 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

a Stem and Leaf display of temp 180 appears to be a typical value for this data The distribution is ... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Document Format (1 attachment)

Word file Icon

1172-M-S-L-R(9095).docx

120 KBs Word File

Students Have Also Explored These Related Statistics Questions!