Question: The equation (deterministic) for a straight line is y = 0 + 1x If the line passes through the point 1 -2, 42, then x
y = β0 + β1x
If the line passes through the point 1 -2, 42, then x = -2, y = 4 must satisfy the equation; that is,
4 = β0 + β1(-2)
Similarly, if the line passes through the point (4, 6), then x = 4, y = 6 must satisfy the equation; that is,
6 = β0 + β1(4)
Use these two equations to solve for b0 and b1; then find the equation of the line that passes through the points 1 -2, 42 and (4, 6).
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