Question: The fact that for any linear map the rank plus the nullity equals the dimension of the domain shows that a necessary condition for the
That is, where h: V W is onto, the dimension of W must be less than or equal to the dimension of V.
(a) Show that this (strong) converse holds: no gain in dimension implies that there is a homomorphism and, further, any matrix with the correct size and correct rank represents such a map.
(b) Are there bases for R3 such that this matrix
.png)
represents a map from R3 to R3 whose range is the xy plane subspace of R3?
1 0 0
Step by Step Solution
3.25 Rating (180 Votes )
There are 3 Steps involved in it
a This is immediate from Theorem 24 b Yes This is immediate f... View full answer
Get step-by-step solutions from verified subject matter experts
Document Format (1 attachment)
961-M-L-A-L-S (5444).docx
120 KBs Word File
