The fit in Prob. 15.9 gives S(r) 3i = 1 Ci Gi (r), where W(r) is a 1s STO with orbital exponent 1 and

The fit in Prob. 15.9 gives S(r) ≈ Σ3i = 1 Ci Gi (r), where W(r) is a 1s STO with orbital exponent 1 and Gi is a 1s GTO with orbital exponent αi. Let S(r, ζ) = ζ3/2π-1/2e- ζr. Let Gi (r,ζ) function obtained by replacing αi in Gi(r) by αiζ2. Show that S(r, ζ) ≈ Σ3i = 1 Ci Gi (r, ζ).