Question: The lens maker??s equation for a lens with index n1 immersed in a medium with index n2 takes the form A thin diverging glass (index
The lens maker??s equation for a lens with index n1 immersed in a medium with index n2 takes the form
A thin diverging glass (index = 1.50) lens with R1 = ?? 3.00 m and R2 = ?? 6.00 m is surrounded by air. An arrow is placed 10.0 m to the left of the lens. (a) Determine the position of the image. Repeat part (a) with the arrow and lens immersed in (b) Water (index = 1.33); (c) A medium with an index of refraction of 2.00. (d) How can a lens that is diverging in air be changed into a converginglens.
R2 n2
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a b c d Observe from equation 1 that f 1 n 2 and f 0 when n 1 2 ... View full answer
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