The position of a particle of mass m = 0.8 kg as a function of time is
Question:
The position of a particle of mass m = 0.8 kg as a function of time is r = x i + y j = R sin ωt i + R cos ωt j, where R = 4.0 m, and ω = 2π s-1.
(a) Show that this path of the particle is a circle of radius R with its center at the origin.
(b) Compute the velocity vector. Show that vx/vy = -y/x.
(c) Compute the acceleration vector and show that it is in the radial direction and has the magnitude v2/r.
(d) Find the magnitude and direction of the net force acting on the particle.
Step by Step Answer:
a See Problem 598 r R 4 m b See Problem 598 v R cos t i R sin t j 8 cos ...View the full answer
Fundamentals of Ethics for Scientists and Engineers
ISBN: 978-0195134889
1st Edition
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