The position of a particle of mass m = 0.8 kg as a function of time is

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The position of a particle of mass m = 0.8 kg as a function of time is r = x i + y j = R sin ωt i + R cos ωt j, where R = 4.0 m, and ω = 2π s-1

(a) Show that this path of the particle is a circle of radius R with its center at the origin. 

(b) Compute the velocity vector. Show that vx/vy = -y/x. 

(c) Compute the acceleration vector and show that it is in the radial direction and has the magnitude v2/r. 

(d) Find the magnitude and direction of the net force acting on the particle.

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