Question: The position vector for a proton is initially r = 5.0i 6.0j + 2.0k and then later is r = 2.0i + 6.0i

The position vector for a proton is initially r = 5.0i – 6.0j + 2.0k and then later is r = – 2.0i + 6.0i + 2.0k, all in meters.

(a) What is the proton's displacement vector, and

(b) To what plane is that vector parallel?

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