The rate law for the substitution reaction of 2-bromobutane and HO- in 75% ethanol and 25% water
Question:
rate = 3.20 × 10-5[2-bromobutane][HO-] + 1.5 × 10-6[2-bromobutane]
What percentage of the reaction takes place by the mechanism when these conditions
a. [HO ] = 0.001 M
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a SN2 SN2 SN1 SN2 SN2 SN1 k2brom...View the full answer
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