The reaction N2(g) + 3H2(g) 2NH3(g) is spontaneous at room temperature but becomes nonspontaneous at a
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N2(g) + 3H2(g) → 2NH3(g)
is spontaneous at room temperature but becomes nonspontaneous at a much higher temperature. From this fact alone, obtain the signs of ∆Ho, and ∆So, assuming that ∆Ho and ∆o do not change much with temperature. Explain your reasoning.
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At low room temperature G or H TS must be negative but at ...View the full answer
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