Treatment of 3, 4-dibromohexane with strong base leads to loss of 2 equivalents of HBr and formation
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Treatment of 3, 4-dibromohexane with strong base leads to loss of 2 equivalents of HBr and formation of a product with formula C6H10. Three products are possible. Name each of the three, and tell how you would use 1H and 13C NMR spectroscopy to help identify them. Flow would you use UV spectroscopy?
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CH3CHCCCHCH3 3Hexyne 1H NMR 13C NMR 2 peaks triplet qu...View the full answer
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