Two batteries with emf E1 and E2 and internal resistances r1 and r2 are connected in parallel.
Question:
Two batteries with emf E1 and E2 and internal resistances r1 and r2 are connected in parallel. Prove that if a resistor is connected in parallel with this combination, the optimal load resistance (the resistance at which maximum power is delivered) is R = r1r2/(r1 + r2).
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Let I 1 be the current delivered by ...View the full answer
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