Question: Two constant forces act on a 5.00-kg object moving in the xy plane, as shown in Figure P7.60. Force F1 is 25.0 N at 35.0°,

Two constant forces act on a 5.00-kg object moving in the xy plane, as shown in Figure P7.60. Force F1 is 25.0 N at 35.0°, while F2 is 42.0 N at 150°. At time t = 0, the object is at the origin and has velocity (4.00i + 2.50 j) m/s.
(a) Express the two forces in unit vector notation. Use unit-vector notation for your other answers.
(b) Find the total force on the object.
(c) Find the object€™s acceleration. Now, considering the instant t = 3.00 s,
(d) Find the object€™s velocity,
(e) Its location,
(f) Its kinetic energy from ½ mvf 2, and
(g) Its kinetic energy from ½ mvi2 + ∑F∙Δr.

Two constant forces act on a 5.00-kg object

150 35.0 x: Figure P7.60

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a F 250 Ncos 350i sin350j 2051 1439 F 420 Ncos 150 i sin150j 3641 ... View full answer

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