Question: Under certain rare circumstances, a nucleus can decay by emitting a particle more massive than an alpha particle. Consider the decays 223Ra ?? 209Pb +

Under certain rare circumstances, a nucleus can decay by emitting a particle more massive than an alpha particle. Consider the decays 223Ra ?? 209Pb + 14C and 223Ra ?? 219Rn + 4He. Calculate the Q value for the

(a) First and

(b) Second decay and determine that both are energetically possible.

(c) The Coulomb barrier height for alpha-particle emission is 30.0MeV. What is the barrier height for 14C emission? The needed atomic masses are

HC 14.003 24 u *He 4.002 60 u 223 Ra 223.018 50

HC 14.003 24 u *He 4.002 60 u 223 Ra 223.018 50 u 200Pb 208.981 07 u 21Rn 219.009 48 u

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