Under certain rare circumstances, a nucleus can decay by emitting a particle more massive than an alpha

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Under certain rare circumstances, a nucleus can decay by emitting a particle more massive than an alpha particle. Consider the decays 223Ra ?? 209Pb + 14C and 223Ra ?? 219Rn + 4He. Calculate the Q value for the

(a) First and

(b) Second decay and determine that both are energetically possible.

(c) The Coulomb barrier height for alpha-particle emission is 30.0MeV. What is the barrier height for 14C emission? The needed atomic masses are

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Fundamentals of Physics

ISBN: 978-0471758013

8th Extended edition

Authors: Jearl Walker, Halliday Resnick

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Question Posted: Feb 19, 2011 04:27 AM

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Under certain rare circumstances, a nucleus can decay by emitting a particle more massive than an alpha

Question:

HC 14.003 24 u *He 4.002 60 u 223 Ra 223.018 50 u 200Pb 208.981 07 u 21°Rn 219.009 48 u

Step by Step Answer:

a For the first reaction Q mmpmc c 22301850u2089...View the full answer

Fundamentals of Physics

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