Use implicit differentiation to find an equation of the tangent line to the curve at the given point 25 x xy y 3 (1, 1) (ellipse) 3D 26 x 2xy y x 2 (1,2) (hyperbola) 28 x y 3 4 ( 3,3, 1) 27 x y (2x 2y x) (0 ) (cardioid) (astroid) 8 29 2(x y) 25(x y) 30 y(y 4) x(x 5) (3 1) (0, 2) (devil's curve) (lemniscate)

Question: Use implicit differentiation to find an equation of the tangent line to the curve at the given point. 25. x + xy + y =

Use implicit differentiation to find an equation of the tangent line to the curve at the given point.

25. x + xy + y = 3. (1, 1) (ellipse) %3D 26. x² + 2xy – y + x = 2. (1,2) (hyperbola) 28. x + y/3 = 4 (-3,3, 1) 27. x

25. x + xy + y = 3. (1, 1) (ellipse) %3D 26. x² + 2xy – y + x = 2. (1,2) (hyperbola) 28. x + y/3 = 4 (-3,3, 1) 27. x

25. x + xy + y = 3. (1, 1) (ellipse) %3D 26. x + 2xy y + x = 2. (1,2) (hyperbola) 28. x + y/3 = 4 (-3,3, 1) 27. x + y = (2x? + 2y x)? (0.) (cardioid) (astroid) 8. 29. 2(x* + y) = 25(x - y) 30. y(y-4) x(x* - 5) (3. 1) (0, -2) (devil's curve) (lemniscate)

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25 x xy y 3 2x xy y 12yy 0xy 2yy 2x y 2xy x 2y an equation of the tangent line is y 1121 or y x 2 yx ... View full answer

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