Question: Use the equation from Problem 11-21, where M is Cu2+ and L is acetate. Consider adding 0.500 M acetate to 10.00 mL of 0.050 0

Use the equation from Problem 11-21, where M is Cu2+ and L is acetate. Consider adding 0.500 M acetate to 10.00 mL of 0.050 0 M Cu2+ at pH 7.00 (so that all ligand is present as CH3CO2- , not CH3CO2H). Formation constants for Cu(CH3CO2)- and Cu(CH3CO2)2 are given in Appendix I. Construct a spreadsheet in which the input is pL and the output is (a) [L]; (b) VL; (c) [M]; (d) [ML]; (e) [ML2]. Prepare a graph showing concentrations of L, M, ML, and ML2 as VL ranges from 0 to 3 mL.

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Concentration M 006 005 004 003 002 001 000 0 M ML 1 2 Volume of L added L ML 2 3 A 1 Copperacetate ... View full answer

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