Question: Use the Intermediate Value Theorem to show that x3 - 7x2 + 14x - 8 = 0 has at least one solution in the interval

Use the Intermediate Value Theorem to show that x3 - 7x2 + 14x - 8 = 0 has at least one solution in the interval [0, 5]. Sketch the graph of y = x3 - 7x2 + 14x - 8 over [0, 5]. How many solutions does this equation really have?

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