Use the modified algorithm developed in Exercise 9 to solve the linear systems in Exercise 8.
In Exercise 7
a. 2x1 − x2 = 3,
−x1 + 2x2 − x3 = −3,
− x2 + 2x3 = 1.
b. 4x1 + x2 + x3 + x4 = 0.65,
x1 + 3x2 − x3 + x4 = 0.05,
x1 − x2 + 2x3 = 0,
x1 + x2 + 2x4 = 0.5.
c. 4x1 + x2 − x3 = 7,
x1 + 3x2 − x3 = 8,
−x1 − x2 + 5x3 + 2x4 = −4,
2x3 + 4x4 = 6.
d. 6x1 + 2x2 + x3 − x4 = 0,
2x1 + 4x2 + x3 = 7,
x1 + x2 + 4x3 − x4 = −1,
−x1 − x3 + 3x4 = −2.