Question: Use the Nonlinear Shooting Algorithm with h = 0.25 to approximate the solution to the boundary-value problem Y = 2y3, 1 x 0,
Y" = 2y3, −1 ≤ x ≤ 0, y(−1) = 1/2, y(0) = 1/3.
Compare your results to the actual solution y(x) = 1/(x + 3).
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