Question: Using the same approach as in the previous exercise, predict the form of the multiplets arising from the terms x, 21Zx, 41z2zx and 81z2z3zx m
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cos (A) cos (B)Icos (A B) + cos (A -B)] sin (A) sin (B) [cos (A-B)-cos (A + B)] sin (A) cos (B)(A B) +sin (A - B)] 2 sin (A) cos (A 2A) cos (A) - sin2 (A) sin2 (A) sin (2A) cos2 (A),[1+cos ( 2A) cos (-A ) [1-cos (2A)] COS cos (A ) sin(-A)--sin(A).
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We need to be intelligent about the way we approach this or we will waste a lot of time computing terms which ultimately do not end up as S x The evol... View full answer
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