Using the value of Kp computed in Problem 10.18, obtain a plot of the current versus time
Question:
In Problem 18
KT = Kb = 0.2 N.m/A
cm = 5 x 10-4 N.m.s/rad
cL = 2 x 10-3
Ra = 0.8 Ω
La = 4 x 10-3 H
lm = 5 x 10-4
It = 10-4
IL = 5 x 10-3 kg-m2
N = 2
Ka = 10 V/V
Ktach = 20 V.s/rad
Kd = 10 V/rad
Kd = 2 rad/(rad/s)
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The value from Problem 1019 is K P 36772 From Example 1086 And thu...View the full answer
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