Question: What is the percent difference between the classical kinetic energy KcI = m0(2, and the correct relativistic kinetic energy, K = m0c2 / (1

What is the percent difference between the classical kinetic energy KcI = ½ m0(2, and the correct relativistic kinetic energy, K = m0c2 / (1 - (2 / c2 - m0c2, at a speed of

(a) 0.10c and

(b) 0.90c?

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