Question: y2 + 4xy + 4x4 = 0 at all points where x = -0.5, x = 0.5, x = -1, and x = 1. What

y2 + 4xy + 4x4 = 0 at all points where x = -0.5, x = 0.5, x = -1, and x = 1. What happens at x = 0?
Use implicit differentiation to find the slope of the tangent to the above relations at the given points. What do the shapes look like?

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