1. Using 1/f = 1/so+1/st , so = 3.50 cm, and st = 7.25 cm, find f.
2. Using 1/f = 1/so+1/st , so = 8.50 cm, and f = 25.0 cm, find st
3. Using M = ht/ho = –st/so, ho = 6.50 cm, st = 7.50 cm, and so = 1.40cm, find ht.
4. If an object is 3.75 m tall and 7.35 m from a large mirror with an image formed 4.35 m from the mirror, what is the height of the image?
5. An object 43.0 cm tall is located 23.4 cm from a concave mirror with focal length 21.4 cm.
(a) Where is the image located?
(b) How high is the image?
6. An object and its image in a concave mirror are the same height, but inverted, when the object is 45.3 cm from the mirror. What is the focal length of the mirror?
7. The angle of incidence of light passing from air to a liquid is 41.0°. The angle of refraction is 29.0°. Find the index of refraction of the liquid.
8. If the index of refraction of a liquid is 1.44, find the speed of light in that liquid.
9. If the critical angle of a liquid is 45.6°, find the index of refraction for that liquid.
10. If the index of refraction of a substance is 1.50, find its critical angle of incidence.
11. A converging lens has a focal length of 12.0 cm. If it is placed 36.0 cm from an object, how far from the lens will the image be formed?