A 1.50.kg grinding wheel is in the form of a solid cylinder of radius 0.100 m. (a)

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A 1.50.kg grinding wheel is in the form of a solid cylinder of radius 0.100 m.
(a) What constant torque will bring it from rest to an angular speed of 1200 rev/n in 2.5 s?
(b) Through what angle has it turned during that time?
(c) Use Eq. (10.21) to calculate the work done by the torque.
(d) What is the grinding wheel's kinetic energy when it is rotating at 1200 rev/min? Compare your answer to the result in part (c).
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College Physics

ISBN: 978-0321601834

7th edition

Authors: Jerry D. Wilson, Anthony J. Buffa, Bo Lou

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