Question: A 1.80-kg connecting rod from a car engine is pivoted about a horizontal knife edge as shown in Fig. 13.33. The center of gravity of

A 1.80-kg connecting rod from a car engine is pivoted about a horizontal knife edge as shown in Fig. 13.33. The center of gravity of the rod was located by balancing and is 0.200 m from the pivot. When the rod is set into small-amplitude oscillation, it makes 100 complete swings in 120 s. Calculate the moment of inertia of the rod about the rotation axis through the pivot.

d = 0,200 m cg

d = 0,200 m cg

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