A 0.60-kg basketball is dropped out of a window that is 6.1 m above the ground. The
Question:
(a) How much work is done on the ball by its weight? What is the gravitational potential energy of the basketball, relative to the ground, when it is
(b) Released
(c) Caught?
(d) How is the change (PEf - PE0) in the ball's gravitational potential energy related to the work done by its weight?
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REASONING The work done by the weight of the basketball is given by Equation 61 as W F cos s where F ...View the full answer
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