A 95% CI for true average amount of warpage (mm) of laminate sheets under specified conditions was

Question:

A 95% CI for true average amount of warpage (mm) of laminate sheets under specified conditions was calculated as (1.81, 1.95), based on a sample size of n = 15 and the assumption that amount of warpage is normally distributed.
a. Suppose you want to test H0: μ = 2 versus Ha: μ ≠ 2 using α = .05. What conclusion would be appropriate, and why?
b. If you wanted to use a significance level of .01 for the test in (a), what conclusion would be appropriate?
Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Question Posted: