a) A 75.0mL-volume of 0.200M NH3 (Kb= 1.8*10^-50 is titrated with 0.500HNO3. Calculate the pH after the
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b) A 52.0mL-volume of 0.35M CH3COOH (Ka-1.8*10^-5) is titrated with 0.40M NaOH. Calculate the pH after the addition of 33.0mL of NaOH.
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a Initial moles of NH3 751000 x 0200 0015 mol Moles of HNO3 added 171000 x 0...View the full answer
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