Question: A 3.0 kg particle with velocity v = (5.0 m/s) i - (6.0 m/s) j is at x = 3.0 m, y = 8.0 m.

A 3.0 kg particle with velocity v = (5.0 m/s) i - (6.0 m/s) j is at x = 3.0 m, y = 8.0 m. It is pulled by a 7.0 N force in the negative x direction. About the origin, what are?
(a) The particle's angular momentum,
(b) The torque acting on the particle, and
(c) The rate at which the angular momentum is changing?

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