A machine carries a 4.0 kg package from an initial position of d1= (0.50m)i + (0.75m)j + (0.20 m)k at t = 0 to a final position of df = (7.50 m)i + (12.0 m)j + (7 .20 m)k at t = 12s. The constant force applied by the machine on the package is F = (2.00 N)i + (4.00 N)j + (6.00 N)k. For that displacement, find
(a) The work done on the package by the machine's force and
(b) The average power of the machine's force on the package.