Question: A metal ion buffer was prepared from 0.030 M ML and 0.020 M L, where ML is a metal ligand complex and L is free

A metal ion buffer was prepared from 0.030 M ML and 0.020 M L, where ML is a metal ligand complex and L is free ligand.
M + L ⇌ ML Kf = 4.0 × 108
Calculate the concentration of free metal ion, M, in this buffer.

Step by Step Solution

3.41 Rating (173 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

MLML 40 1... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Document Format (1 attachment)

Word file Icon

878-E-C-E-E-C (2061).docx

120 KBs Word File

Students Have Also Explored These Related Chemical Engineering Questions!