a. Starting with isopropylacetylene, how could you prepare the following alcohols? 1. 2-methyl-2-pentanol 2. 4-methyl-2-pentanol b. In
Question:
1. 2-methyl-2-pentanol
2. 4-methyl-2-pentanol
b. In each case a second alcohol would also be obtained. What alcohol would it be?
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a 1 2 4methyl2pentanol can be prepared by the same synthesis used to prepare 2methyl2pe...View the full answer
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