a. The ∆G° for conversion of "axial" fluorocyclohexane to "equatorial" fluorocyclohexane at 25°C is - 0.25 kcal/mol(or - 1.05 kJ/mo). Calculate the percentage of fluorocyclohexane molecules that have the fluoro substituent in the equatorial position.
b. Do the same calculation for isopropylcyclohexane (whose ∆G° at 25°C is - 2.1 kcal/mol, or - 8.8 kJ/mol).
c. Why does isopropylcyclohexane have a greater percentage of the conformer with the substituent in the equatorial position?