(a) Use Newtons method with x1 = 1 to find the root of the equation x3 ...
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(b) Solve the equation in part (a) using x1 = 0.6 as the initial approximation.
(c) Solve the equation in part (a) using x1 = 0.57. (You definitely need a programmable calculator for this part.)
(d) Graph f(x) = x3 – x – 1 and its tangent lines at x1 = 1. 0.6 And 0.57 to explain why Newton’s method is so sensitive to the value of the initial approximation.
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x x 1 rx10 fx x 21 fx 3x a x 1 x2 153 1347826 x4 1325200 xs 1324718x6 1 so n1 In x In 3x2 1 1 I6 T8 ...View the full answer
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Related Book For
Business Math
ISBN: 978-0133011203
10th edition
Authors: Cheryl Cleaves, Margie Hobbs, Jeffrey Noble
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