According to Pauling, the AB bond energy is equal to the average of the AA and BB
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BE(A–B) = 1/2 [BE(A–A) + BE(B–B)] + k(XA XB)2]
Here XA and XB are the electronegativities of atoms A and B, and k is a constant equal to 98.6 kJ. Assume that the electronegativity of H is 2.1. Use the formula to calculate the electronegativity of oxygen.
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Use the OH bond and its bond energy of 459 kJmol to calculat...View the full answer
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