Question: An ac generator is in series with a capacitor and an inductor in a circuit with negligible resistance. (a) Show that the charge on the
An ac generator is in series with a capacitor and an inductor in a circuit with negligible resistance.
(a) Show that the charge on the capacitor obeys the equation
-1.png)
(b) Show by direct substitution that this equation is satisfied by Q = Qmax cos ωt if
-2.png)
(c) Show that the current can be written as I = Imax cos (ωt – δ), where
-3.png)
and δ = –90° for ω < ω0 and δ = 90o for ω > ω0.
d2Q Q L- di2 = Emay cos ot
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a From Kirchhoffs law L dI dt Q C E E max cos t Bu... View full answer
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