Question: An alpha particle (q = +2e, m = 4.00 u) travels in a circular path of radius 4.50 cm in a uniform magnetic field with

An alpha particle (q = +2e, m = 4.00 u) travels in a circular path of radius 4.50 cm in a uniform magnetic field with B = 1.20 T. Calculate

(a) Its speed,

(b) Its period of revolution,

(c) Its kinetic energy, and

(d) The potential difference through which it would have to be accelerated to achieve this energy.

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a Using Eq 2816 we obtain V rqB ma 2eB 400 u 2450102 m16... View full answer

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