An aqueous glycerol solution weighing 100.0 mg was treated with 50.0 mL of 0.083 7 M Ce
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An aqueous glycerol solution weighing 100.0 mg was treated with 50.0 mL of 0.083 7 M Ce4+ in 4 M HClO4 at 60°C for 15 min to oxidize the glycerol to formic acid:
The excess Ce4+ required 12.11 mL of 0.044 8 M Fe2+ to reach a ferroin end point. What is the weight percent of glycerol in the unknown?
Transcribed Image Text:
CH, — CH— СH, | HCO,H OH ОН ОН Formic acid Glycerol FM 92.095
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One mole of glycerol requires eight moles of Ce 4 500 mL of 0083 7 M Ce 4 418...View the full answer
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