Question: Consider a variation on the code in Figure 15.5, in which the string concatenation inside the while loop is reversed: str = foobar; i =
Consider a variation on the code in Figure 15.5, in which the string concatenation inside the while loop is reversed:
str = foobar; i = str.search(/[aeiou]/); while (i != -1) {str = str.substring(0, i) + '*' + str.substring(i+1, str.length); i = str.search(/[aeiou]/);}
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