Question: Consider a particle of mass m whose motion starts from rest in a constant gravitation field. If a resisting force proportional to the square of

Consider a particle of mass m whose motion starts from rest in a constant gravitation field. If a resisting force proportional to the square of the velocity (i.e., kmv2) is encountered, show that the distance s the particle falls in accelerating from v0 to v2 is given by


g- kuj - kuj_ s(vo u) In 2k

g- kuj - kuj_ s(vo u) In 2k

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The equation of motion is kmv mg This equation can be solved ex... View full answer

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