Question: Considering the following pKa values,31 explain why dilute sodium methoxide (NaOCH3) and sodium ethoxide (NaOCH2CH3) are leveled to the same base strength in aqueous solution.

Considering the following pKa values,31 explain why dilute sodium methoxide (NaOCH3) and sodium ethoxide (NaOCH2CH3) are leveled to the same base strength in aqueous solution. Write the chemical reactions that occur when these bases are added to water.
CH3OH pKa = 15.54
CH3CH2OH pKa = 16.0
HOH pKa = 15.74 (for Ka [H+][OH-]/[H2O])

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